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Re: MASN - Allowable Shear
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- Subject: Re: MASN - Allowable Shear
- From: Dave Anderson <dnae(--nospam--at)earthlink.net>
- Date: Sun, 05 Oct 1997 20:31:04 -0700
Joe McCormick wrote: > >The solution for the sample question was as follows: > > > > Fv=1.0*SQR(f'm/2) > > > >My interpretation of the code is: > > > > Fv=[1.0*SQR(f'm)]/2 > > > >Which is right? > > The solution for the sample question is the correct interpretation of code > for uninspected masonry construction. Think of a converse situation to > explain this rational: if you had an f'm twice as high, you would NOT > simply multiply the original value of Fv by 2! That would produce incorrect > results. Therefore, it would be just as INCORRECT to devide Fv by 2 when > you have an f'm that is half as high as the original value. > > With regard to anchor bolts and hardware, be sure to read the footnotes > under tables carefully... for example UBC table 21-E-1 allowable tension > values are for work WITH OR WITHOUT special inspection. Hope this helps! > > Best Regards, > > Joe McCormick > > Fv=[1.0*SQR(f'm)]/2 this the correct answer Fv=0.5(SQR(f'm)) D.A.
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