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Re: MASN - Allowable Shear

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Joe McCormick wrote:

> >The solution for the sample question was as follows:
> >
> >       Fv=1.0*SQR(f'm/2)
> >
> >My interpretation of the code is:
> >
> >       Fv=[1.0*SQR(f'm)]/2
> >
> >Which is right?
>
> The solution for the sample question is the correct interpretation of code
> for uninspected masonry construction.  Think of a converse situation to
> explain this rational:  if you had an f'm twice as high, you would NOT
> simply multiply the original value of Fv by 2!  That would produce incorrect
> results.  Therefore, it would be just as INCORRECT to devide Fv by 2 when
> you have an f'm that is half as high as the original value.
>
> With regard to anchor bolts and hardware, be sure to read the footnotes
> under tables carefully... for example UBC table 21-E-1 allowable tension
> values are for work WITH OR WITHOUT special inspection.  Hope this helps!
>
> Best Regards,
>
> Joe McCormick
>
>

  Fv=[1.0*SQR(f'm)]/2

this the correct answer

Fv=0.5(SQR(f'm))


D.A.