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# Re: modeling of 3d-frame with shearwall

• To: seaint(--nospam--at)seaint.org
• Subject: Re: modeling of 3d-frame with shearwall
• From: Rudra Nevatia <nanditan(--nospam--at)giasbma.vsnl.net.in>
• Date: Thu, 30 Jul 1998 15:04:09 +0500 (IST)
• Cc: jerome.tan(--nospam--at)PAREURO.COM

Jerome,

I have a two questions :

1. Is it all right to divide a shear wall into plate
elements which are one storey high and one bay wide
or should a more refined mesh be used ?

2. Is it all right to connect beam elements (13-15) and
(7-13) to the plate element (7-8-13-14) ?

Rudra Nevatia

On Wed, 29 Jul 1998 jerome.tan(--nospam--at)PAREURO.COM wrote:

>      Siamak,
>
>      You must prepare at least three or four nodes to identify the plate
>      element. Then assign the material properties and thickness. You also
>      have to identify it if its a membrane or a plate element. For walls,
>      it should be plate or solid. I usually assign plate.
>
>      Say you have a 26' long x 12' wide and 20' high (one storey is 3m)
>      building and the West face is a shear wall.
>
>      <-- 12'--->    <-----------26' ----------->      <---12'-->
>      14        13    13/14        15/16       17/18  18        17
>      +---------+    +++++++++++++++++++++++++++      +---------+
>      +         +    +            +            +      +         +
>      +         +    +            +            +      +         +
>      +    B    +    +            +            +      +         +
>      +8        +7   +7/8         +9/10        +11/12 +12       +11
>      ----------+    +------------+------------+      +---------+
>      +         +    +            +            +      +         +
>      +    A    +    +            +            +      +         +
>      +         +    +            +            +      +         +
>      +2        +1   +1/2         +3/4         +5/6   +6        +5
>
>
>         West Face           North & South Face           East Face
>         (SWall)
>
>        At the west face, the A (PLATE ELEM 1 ) Plate would be made of node 2 1
>        7 8; the B (PLATE ELEM 2) plate by 8 7 13 14. You can assign the
>        thickness of, say 10" and E=3260 KSI
>
>         So the input would look like :
>
>         SHELL
>         NM=1
>         1 E = 3300
>         1  JQ = 2 1 7 8 TH = 10
>         2  JQ = 8 7 13 14 TH =10
>