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Re: Soil Pressure

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Sorry, last post contained nothing (I hit the wrong key before anything was
typed).  Based on the data your geotech gave you, the equivalent pressure at
the base of the wall (assuming 8 ft. ht. as you stated) due to 35 pcf
equivalent fluid pressure is 8 x 35 = 280 psf with a triangular distribution
diminishing to zero at the top and therefore an overall horizontal total force
= 1/2 x 280 x 8  = 1,140 plf (i.e. pounds per horizontal linear foot of wall).
How did you arrive at 75 psf for an answer??  How this force is resisted and
what the reaction/shear /moment distribution is of course a function of
whether or not the wall is a cantilered one from its base or restrained its
top by the floor framing system.  Strictly speaking of course this would also
affect the soil pressure distribution itself, but the geotech presumably just
assumed triangular distribution in either case, based on how the data appears
to be stated.  

Now, in addition to the above there will be added horizontal pressure of 15H
(psf), where H is height of surcharge, NOT wall, with a total horizontal force
of 8 x 15H (plf).  Since you didn't give the surcharge height, the numerical
values are not obtainable.

The inverted triangular earthquake equivalent fluid pressure of 20 pcf will
not increase the horizontal pressure at the base of the wall, but will impose
an additional total horizontal force of 1/2 x 8^2 @ 20 pcf = 640 plf applied @
2/3 the wall height.

Does that answer your question?