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Re: Church bells

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A good approximation would be .75* (rho)*v*d = 1000*(h/2) where rho is the
density of the counter weight material , v=volume of counterwts and d=
distance from rotating axis of the center of gravity of the counter weights
and h=height of the bell.  I used .75 to provide for easier swing and to not
rotate (360) and to allow for fine tuning at the moment arm (distance from
the rotating axis of the arm that the rope is attached to).  This distance
would be the easiest to change for easy ringing.  Once you know rho and v
then solve for d .
d = (1333 (h/2)) / (rho * v)           ( approximate)

                                                            Greg Smith
-----Original Message-----
From: Alex C. Nacionales <anacio(--nospam--at)>
To: seaint(--nospam--at) <seaint(--nospam--at)>
Date: Wednesday, January 27, 1999 2:47 PM
Subject: Church bells

>I am reconstructing several bells in old church  here. The bells
>are about 1000 lbs. The bells have bullet holes about 1
>inch in diameter and the concrete counterweights were destroyed.
>1. How heavy should the counterweights be so that the bells will stay
>upright when at rest and swing 45 deg. on each side with a minimum push.
>2. How to repair the holes to improve the bell tones. The bell metal is a
>mixture of copper and tin. I am planning of welding it using
>electrodes with matching base metal.
>I will appreciate any help from you.
>Alex C. Nacionales, C.E.
>Iloilo City, Philippines