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# RE: Church bells

• To: <seaint(--nospam--at)seaint.org>
• Subject: RE: Church bells
• From: "Alex C. Nacionales" <anacio(--nospam--at)skyinet.net>
• Date: Thu, 28 Jan 1999 14:08:44 +0800

```Greg,

You are assuming from your formula that the C.G. of the Bell is at
h/2 which closer to 2/3h  I think because the bell is wider and thicker
at the lower portion.

Thank you for your formula and thanks to the others who contributed.

Alex C. Nacionales, C.E.
Iloilo City

> -----Original Message-----
> From: Greg Smith [mailto:strusup(--nospam--at)gte.net]
> Sent: Thursday, January 28, 1999 6:19 AM
> To: seaint(--nospam--at)seaint.org
> Subject: Re: Church bells
>
>
> A good approximation would be .75* (rho)*v*d = 1000*(h/2) where rho is the
> density of the counter weight material , v=volume of counterwts and d=
> distance from rotating axis of the center of gravity of the
> counter weights
> and h=height of the bell.  I used .75 to provide for easier swing
> and to not
> rotate (360) and to allow for fine tuning at the moment arm (distance from
> the rotating axis of the arm that the rope is attached to).  This distance
> would be the easiest to change for easy ringing.  Once you know rho and v
> then solve for d .
> d = (1333 (h/2)) / (rho * v)           ( approximate)
>
>                                                             Greg Smith

```