Need a book? Engineering books recommendations...
Re: shear design[Subject Prev][Subject Next][Thread Prev][Thread Next]
- To: seaint(--nospam--at)seaint.org
- Subject: Re: shear design
- From: "Bill Sherman" <SHERMANWC(--nospam--at)cdm.com>
- Date: 13 Feb 99 12:51:36 -0500
Here's my "proof" of the design for shear-friction reinforcement at non-keyed construction joints: 1. I concur with three general statements made in ACI 318 R11.7.7. which suggest the following: i) where there is direct tension across a joint, reinforcement must be provided to resist the tension in addition to the shear-friction reinforcement; ii) where there is direct compression across a joint, the shear-friction reinforcement may be reduced accordingly; iii) when considering flexure only on a joint, the tension and compression are in equilibrium, i.e. T=C. 2. For shear alone, Av = V/uFy (I will leave "phi" out of the formulas to simplify typing). Av equals the total reinforcement across the joint (tension and compression faces). 3. For tension alone, As = T/Fy. For tension plus shear, Total As = T/Fy + V/uFy. 4. For compression plus shear, V = u(C + AvFy) or Av = V/uFy - C/Fy. 5. Combining shear plus compression plus tension: As = T/Fy + V/uFy - C/Fy. If T and C are due to flexure only, T = C, so As = V/uFy = Av. Thus, shear-friction reinforcement is not affected by flexure.
- Prev by Subject: Re: shear design
- Next by Subject: Re: Shear Modulus
- Previous by thread: Re: shear design
- Next by thread: Re: Advice on Field Experience.