RE: Concrete Frame Rigidity

• To: seaint(--nospam--at)seaint.org
• Subject: RE: Concrete Frame Rigidity
• From: Francis.Ang(--nospam--at)toyota.com.ph
• Date: Fri, 14 May 1999 07:45:00 +0800
• Cc: rlewis(--nospam--at)techteam.org
```If you're using a manual computation, the solution is like solving for the
centroid of a section. That is taking summation of an area*distance to a
specified point. (A(total)*xbar=S(An*xn)). But the area would be changed to
the moment of Inertia. You can then compute for the center of rigidity.

> ----------
> From: 	rlewis(--nospam--at)techteam.org[SMTP:rlewis(--nospam--at)techteam.org]
> Sent: 	Friday, May 14, 1999 4:16 AM
> To: 	seaint(--nospam--at)seaint.org
> Subject: 	Concrete Frame Rigidity
>
> I need a refresher course in lateral load distribution.  I need to find
> the
> center of rigidity of a concrete frame building.  I can't find a reference
> that illustrates how to do this.  All I find is concrete/masonry wall
> illustrations.
>
> I have a 2 story concrete framed structure in the Dominican Republic.  I
> want
> to locate the center of rigidity.  Unfortunately the structure and framing
> is
> not symmetrical so I need to calculate rigidity of the concrete frames.
> It
> is also irregular in plan.  I know rigidity is the reciprocal of
> defection,
> but is there an easy way to calculate this for rigid frames?
>
> I appreciate all insight into this topic.
>
>
>
> __________________________________________________
>
> Richard Lewis, P.E.
> Missionary TECH Team
> rlewis(--nospam--at)techteam.org
>
> The service mission like-minded Christian organizations
> may turn to for technical assistance and know-how.
>
>

```