# RE: Maximum base shear

• To: "'seaint(--nospam--at)seaint.org'" <seaint(--nospam--at)seaint.org>
• Subject: RE: Maximum base shear
• From: "Sherman, William" <ShermanWC(--nospam--at)cdm.com>
• Date: Tue, 9 May 2000 10:03:27 -0400
```The easy answer is "yes".

First it must be recognized that code values are "best estimates" not fixed
maximums. Earthquake engineering is not that precise.

Then, we must break the code formula down into components. The Ca value is
the only variable that relates to ground acceleration. The other factors
relate to how a structure behaves under dynamic ground motion.

I think that you could say that the "design ground acceleration" is Ca =
0.44(1.5) = 0.66g. As per another thread regarding the "seismic margin"
included in the code values, it is expected that a structure could withstand
1.5 times as much ground motion without collapse,

-----Original Message-----
From: Alex Nacionales [ mailto:alexcnac(--nospam--at)skyinet.net
<mailto:alexcnac(--nospam--at)skyinet.net> ]
Sent: Saturday, May 06, 2000 5:56 PM
To: seaint(--nospam--at)seaint.org <mailto:seaint(--nospam--at)seaint.org>
Subject: Maximum base shear

UBC 97 formula 30-5 page 2-14 states that
the base shear need not exceed the value of the following;

V=2.5 Ca I W/R

for zone 4, at less than 2 km from a fault and using
maxumum values of Ca and I, and R=8.5 for SMRF(Concrete) This was 12 in UBC
88

Ca = .44(1.5)
V=Wx2.5x.44(1.5)(1.25)/8.5
V=.243W

This says that  .243G  is a maximum for buildings.

Could this g force be exceeded by an  intensity 7
earthquake?