Return to index: [Subject] [Thread] [Date] [Author]

correction for RE: perforated shear wall equation correction

[Subject Prev][Subject Next][Thread Prev][Thread Next]
Outstanding David!! You are my hero.



It seems the equation works for 1 in the numerator and A & B being used as
fractions.  That is Co=1/[A*(1-3*B)+3*B] where A & B are fractions.

FOR: 90%  & H/2    A=.9  B=.5
Co=1/[.9*(1-3*.5)+3*.5] = 1/[-.45+1.5] = .95




Otherwise Co=100/[A*(100-3*B)/100+3*B] for A & B as %.

Co=100/[90*(100-3*50)/100+3*50] = 100/[-45+150] = .95

IBC  Table 2305.3.7.2 for 90% sheathed, opening height 50% wall height
Co=.95



Outstanding David!! You are my hero.



Scott M Haan  P.E.
Plan Review Engineer
Building Safety Division http://muni.org/building, 
Development Services Department,
Municipality of Anchorage
phone: 907-343-8183   fax: 907-249-7399
mailto:haansm(--nospam--at)ci.anchorage.ak.us

> -----Original Message-----
> From:	David B Merrick [SMTP:mrkgp(--nospam--at)pacbell.net]
> Sent:	Wednesday, March 21, 2001 1:51 PM
> To:	SEAINT
> Subject:	perforated shear wall equaiton correction
> 
> Disregard the previous equation on the perforated shearwall. (I switched
> A&B)
> The equation is
> Co = 100/(B(1-3A)+3A)
> 
> Reference table 2305.3.7.2
> 
> Let A= the ratio of maximum opening height to the wall height.
> That's the value across the top of the chart.
> 
> Let B= percent of full height sheathing to full length of wall.
> That's the left column on chart.
> 
> 
> David Merrick
> Mrkgp(--nospam--at)pacbell.net
> 
> 
> 
>