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# RE: UBC 97 Anchorage to Concrete

• To: <seaint(--nospam--at)seaint.org>
• Subject: RE: UBC 97 Anchorage to Concrete
• From: "Chan, David" <DCHAN(--nospam--at)ladpw.org>
• Date: Tue, 5 Nov 2002 15:35:22 -0800

Thanks for all the responses!

-----Original Message-----
From: C Chan [mailto:seaint_list(--nospam--at)yahoo.com]
Sent: Tuesday, November 05, 2002 3:27 PM
To: seaint(--nospam--at)seaint.org
Subject: RE: UBC 97 Anchorage to Concrete

The circle in question is 12" radius not **diameter**. Isn't it?

The latter. Draw a circle for the cone projection of a single anchor and subtract the areas where concrete does not exist.

-gerard

Santa Clara, CA

-----Original Message-----
From: Chan, David [mailto:DCHAN(--nospam--at)ladpw.org]
Sent: Tuesday, November 05, 2002 2:48 PM
To: seaint(--nospam--at)seaint.org
Subject: UBC 97 Anchorage to Concrete

I am getting a difference in opinion on the calculation of Ap in UBC 97 Section 1923 Anchorage to Concrete and would like the list's opinion.  For discussion sake, assume a 24"x24" block of concrete in plan with an anchor bolt located 3 inches from the south and west edges and embedded 12 inches.  Is the area Ap equal to a circle with a 3 inch radius (corresponding to 3 inch edge distance)?  or is it equal to the overlapping area of a 12 in. diameter circle and the block of concrete (a circle with two sides cut off)?  I personally believe it is the latter, as it represents a more realistic pullout cone.

David
Los Angeles

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