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RE: lintel

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Vlad,

I don't mean to beat this to death, but if you look at figure no. 1 and
determine where the load is supported that is above the opening but OUTSIDE
of the triangle you have almost the same as picture no. 2.  It forms an arch
which is resisted by a horizontal force at the supports.

Jim

> -----Original Message-----
> From: vlad [mailto:simina(--nospam--at)idirect.com]
> Sent: Tuesday, January 28, 2003 8:29 PM
> To: seaint(--nospam--at)seaint.org
> Subject: Re: lintel
>
>
> Dear Jim:
>
> I think you are right, but in this particular situation, my
> understanding of
> the triangular load looks like in fig.1 (see attached) and
> not like in fig.2
> Thank you kindly all for helpful comments
> Regards,
>
> Vlad
> simina(--nospam--at)idirect.com
>
>
> ----- Original Message -----
> From: "Jim Persing" <jpersing(--nospam--at)fhoarch.com>
> To: <seaint(--nospam--at)seaint.org>
> Sent: Tuesday, January 28, 2003 11:28
> Subject: RE: lintel
>
>
> > Vlad,
> >
> > Assumption of a triangular load IS arch action.
> >
> > Jim
> >
> > > -----Original Message-----
> > > From: vlad [mailto:simina(--nospam--at)idirect.com]
> > > Sent: Monday, January 27, 2003 9:08 PM
> > > To: seaint(--nospam--at)seaint.org
> > > Subject: Re: lintel
> > >
> > >
> > > Good point, but I don't think there is an arch action here.
> > > And the wall above the opening is high enough to justify a
> > > triangular shaped
> > > load.
> > > Thank you for the input.
> > >
> > > Vlad
> > > simina(--nospam--at)idirect.com
> > >
> > > ----- Original Message -----
> > > From: "Jim Persing" <jpersing(--nospam--at)fhoarch.com>
> > > To: <seaint(--nospam--at)seaint.org>
> > > Sent: Monday, January 27, 2003 12:49
> > > Subject: RE: lintel
> > >
> > >
> > > > A suggestion was made regarding using arch action for the
> > > lintel design.
> > > > That is fine but be sure there is enough wall on each side
> > > to support the
> > > > horizontal reaction from the arch.  There are also some
> deflection
> > > > compatibility requirements in the UBC for supporting
> > > masonry.  See Section
> > > > 2106.2.9
> > > >
> > > > Jim Persing
> > > >
> > > > > -----Original Message-----
> > > > > From: vlad [mailto:simina(--nospam--at)idirect.com]
> > > > > Sent: Sunday, January 26, 2003 1:15 PM
> > > > > To: seaint(--nospam--at)seaint.org
> > > > > Subject: Re: lintel
> > > > >
> > > > >
> > > > > The opening is 8'-0" wide and the wall is 12" thick.
> > > > > Mt. Richardson suggested 2 angles on each side connected with
> > > > > steel tabs,
> > > > > and so I did.
> > > > > I provided 2-L4"x4"x1/4" (for a moment of 8.9 kNm) connected
> > > > > with tabs @24".
> > > > > Thank you for taking the time to answer.
> > > > >
> > > > > Regards,
> > > > > Vlad
> > > > > simina(--nospam--at)idirect.com
> > > > >
> > > > > Now I think I should put the tabs @32"! (every other block)
> > > > >
> > > > >
> > > > >
> > > > > ----- Original Message -----
> > > > > From: "Stanley E Scholl" <sscholl2(--nospam--at)juno.com>
> > > > > To: <seaint(--nospam--at)seaint.org>
> > > > > Sent: Saturday, January 25, 2003 22:03
> > > > > Subject: Re: lintel
> > > > >
> > > > >
> > > > > > How wide is the door? If a 3'-0" man door, and if the
> > > > > horiz. reinf. is
> > > > > > say at the 8 ft. level and perhaps 2- #4, you may not
> > > need a lintel.
> > > > > >
> > > > > > Stan Scholl, P.E.
> > > > > > Laguna Beach, CA
> > > > > >
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