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Re: CONICAL ROOF SHEATHING

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Two easy ways to solve the castle roof problem. One is to use # 2 tapersawn cedar shingles or take three tab duroid shingles and cut them into individual pieces. You end up with a shingle that is about 9" wide and you apply it like any conventional roofing systems. The other is to have standing seam panels formed in the shape of long arrow heads, the base dimension is about 12" - 0" at the top or apex.   
 
A third way might be to use 3/8", or less, veneer plywood that will curve to the shape, however, you will still have to do the top part as shakes or triangles.

Thor A. Tandy P.Eng MIPENZ
Victoria BC
Canada
email: vicpeng(--nospam--at)telus.net
----- Original Message -----
From: Pat Clark
Sent: Monday, September 29, 2003 6:08 PM
Subject: RE: CONICAL ROOF SHEATHING

24:12 pitch, therefore about 15' tall.
 
 

Patrick Clark, P.E.

Building Concepts, Inc.

1228 Pep Circle

Gardnerville, NV 89410

(775) 782-8886 x22

(775) 782-8833 fax

-----Original Message-----
From: Thor Tandy [mailto:vicpeng(--nospam--at)telus.net]
Sent: Monday, September 29, 2003 5:48 PM
To: seaint(--nospam--at)seaint.org
Subject: Re: CONICAL ROOF SHEATHING

How high is it?

Thor A. Tandy P.Eng MIPENZ
Victoria BC
Canada
email: vicpeng(--nospam--at)telus.net
----- Original Message -----
From: Pat Clark
Sent: Monday, September 29, 2003 4:41 PM
Subject: CONICAL ROOF SHEATHING

Any good ideas on how to sheath a 15' diamter conical roof?  No especially large loads....
 

Patrick Clark, P.E.

Building Concepts, Inc.

1228 Pep Circle

Gardnerville, NV 89410

(775) 782-8886 x22

(775) 782-8833 fax