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RE: Steel HSS Compression Analysis

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AISC LRFD 3rd Ed. does cover ASTM A500 material, which does encompass all hollow structural shapes.  However, in Table 2-1 on page 2-24, the table only lists material properties for A500 Gr. B and Gr. C.  For this material, I am assuming an A500 Gr. A, which comes in at 33 ksi.  However, if I refer back to the AISI Cold Formed Steel Design Manual 1996 Ed. (we really have to get an updated version), I see for shaped tubing, ASTM A500-93 Grade A, the yeild is 39 ksi with an ultimate of 45 ksi.  I guess, that being said, I could use 39 ksi, pending I don't get any more information back about this material.
 
You question is still a good one, though, as there is some conflicting information within AISC, and I'm hoping some of the AISC people who read these can shed some light on this.  Can ASTM A500 Gr. A material be analysed using AISC methods???
 
Sincerely,
David Maynard, PE
Gillette, Wyoming
-----Original Message-----
From: Will Haynes [mailto:gtg740p(--nospam--at)hotmail.com]
Sent: Wednesday, August 17, 2005 4:54 PM
To: seaint(--nospam--at)seaint.org
Subject: RE: Steel HSS Compression Analysis

Can you use the AISC provisions for a non AISC shape like this? If so, then at what point do you have to start using AISI? That is where I would have started.

 

Will


From:  "David Maynard" <davemaynard(--nospam--at)ceincorp.com>
Reply-To:  <seaint(--nospam--at)seaint.org>
To:  <seaint(--nospam--at)seaint.org>
Subject:  Steel HSS Compression Analysis
Date:  Wed, 17 Aug 2005 13:38:36 -0600
>Here's what I got.  I have a tube shape, 2" wide by 4" deep by 14 ga.
>(0.0747" thick).  I'm using LRFD 3rd Ed. Nov. 10, 2000 HSS Design
>Specification found within.  I check my Slenderness Limits as described in
>Table 2.2-1.  Assuming, because this is not an AISC shape, that Fy = 33 ksi,
>I found Lambda r to be 41.5.  My controlling wall slenderness ration, h/t,
>lambda is 50.5, which exceeds the lambda r.
>
>Flipping to section 4.2 of this design spec, I see that if lambda is greater
>than lambda r, for rectangular HSS, Q = effective area/Ag.  It then states
>that the effective area is equal to the summartion of the effective areas of
>the sides using be = <long equation>.
>
>The question that I run into is, what does this mean, "effective area"???
>
>Do I have to use this equation for both wall dimensions, first with b and
>then with h???  Or do I just use this equation as a substitute for b and
>leave h untouched, even though that is the controlling slenderness limit???
>
>And once this question is answered, I'm assuming I just take these adjusted
>dimensions, multiply them by the thickness and combine all four side for an
>effective area.
>
>Right now, and I'm not sure if this is my illness/vacation talking but, this
>just doesn't make any sense to me.  Can someone shed some light on the
>situation???
>
>Sincerely,
>David Maynard, PE
>Gillette, Wyoming
>--
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>
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