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RE: Bolt force in round column[Subject Prev][Subject Next][Thread Prev][Thread Next]
- To: <seaint(--nospam--at)seaint.org>
- Subject: RE: Bolt force in round column
- From: "Garner, Robert" <rgarner(--nospam--at)moffattnichol.com>
- Date: Wed, 11 Jan 2006 10:28:25 -0800
I was thinking of the utility industry that does not grout column baseplates, but relies only on the anchors for tension and compression.
From: Rich Lewis
Thank you all for your responses. I got to thinking about this after I sent the note and came up with the same basic conclusion. What through me off at first was the compression forces are bearing of the column, not the bolt. I was looking at it as a column baseplate with tension bolts, only all the tension bolts were in different locations. I guess if I look at it as just the bolts taking compression and tension I will get an answer pretty close to the real life situation of bolts in tension and column steel bearing in compression.
From: M. David Finley,
P.E., P.A. [mailto:davidfinley(--nospam--at)bizsea.rr.com]
T = P/A + MC/I. You can use that to find the forces in every bolt.
If you are looking for the maximum tension or compression, then it simplifies to
Bolt_Group_Inertia = (Number of Bolts / 8) x (Bolt_Circle_Diameter)^2
Section_Modulus = (Bolt_Group_Inertia) / (Bolt_Circle_Diameter / 2)
Bolt_Force = (Moment / Section_Modulus) + (Axial Load / Number of Bolts) Use correct signs for loads.
I forget the minimum number of bolts for which this is applicable ( 4? ), but from your description, it should be applicable.
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