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identity theft / was: hold downs at perforated shear wall[Subject Prev][Subject Next][Thread Prev][Thread Next]
- To: <seaint(--nospam--at)seaint.org>
- Subject: identity theft / was: hold downs at perforated shear wall
- From: "Haan, Scott M POA" <Scott.M.Haan(--nospam--at)poa02.usace.army.mil>
- Date: Thu, 18 May 2006 16:29:48 -0800
I've told other people this offline but giving all your contact information on this list service is inviting someone in Iraq or the Ukraine or Mexico etc... to take out a home equity line of credit on your house.
From: Joe Grill [mailto:jgrill(--nospam--at)swiaz.com]
Sent: Thursday, May 18, 2006 3:40 PM
Subject: hold downs at perforated shear wall
When using the “perforated shear wall” method of design. The hold down force at the ends of the wall is calculated by dividing the overturning moment to the wall by an adjusted sum of the lengths of the individual lengths of full height segments. Is this hold down force required even if there is adequate dl to restrain overturning? And then how is the resisting moment calculated? Seems kind of like a dumb question, but the hold down force does not use the total length of the wall, but resisting moments would, as I see it anyway.
Can someone explain this to me?
Joseph R. Grill, P.E. (Structural)
Shephard - Wesnitzer, Inc.
Civil Engineering and Surveying
P.O. Box 3924
Sedona, AZ 86340
PHONE (928) 282-1061
FAX (928) 282-2058
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