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# Re: wind load to retaining wall

• To: seaint(--nospam--at)seaint.org
• Subject: Re: wind load to retaining wall
• From: "Jordan Truesdell, PE" <seaint1(--nospam--at)truesdellengineering.com>
• Date: Mon, 09 Oct 2006 16:55:25 -0400

It is not given because for a wall with equal heights on both sides or for a sign the positive and negative pressures are not salient to the analysis - only the net total pressure is. The only place it is mentioned is for C&C loads (on a building), as you need to know which direction the pressure is going on either side of the building. For a flat plate in a free stream, the Cp is 2.0. This is in line with the sign formula topping out at about 1.95 when it's not near the ground (going by memory here). Since the force on a unit area is simply the static pressure (1/2 x density x v^2), or a Cp = 1.0, it follows that the remainder of the force is frictional drag, boundary layer effects, and "suction" on the back side, which happens to be equal to static pressure (1+1=2). This case is a little more complicated because we have a boundary with zero velocity enforced at the bottom, so the Cp = 1.3. I'd bet a dollar that the force is distributed approximately parabolically from the top (at Cp=2) to the bottom (Cp=0), within say 20%. Integrating over the area would get you about 1.3. If I had five minutes to come up with an answer, I'd do a linear max-to-zero on both sides with half the force, add 20% and call it a day. If I had one minute, I'd use the full force and add a couple of extra bars to the wall. ;-)
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Jordan

jrgrill(--nospam--at)cableone.net wrote:
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Yes, but what is it, it is not specified in ASCE for this application.

Joe

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