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RE: Sole plate nailing

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I’ve never looked at it that way, but the difficulty I see is that, if you transfer the load from the sill plate into the floor WSP, the length of penetration is only the thickness of the WSP.


I *think* the (analytical) mechanism is that the shear wall load is transferred from the SW into the sole plate into the rim/blocking and the floor diaphragm load is transferred from the floor diaphragm into the same rim/blocking, i.e., the loading is additive. Of course, a problem exists when the SPN is 16d at 3” and the floor diaphragm nailing is 10d at 3”. First of all, you will be lucky to get the SPN exactly staggered between the BN and even if you do, the spacing is less than the required penetration and another reduction is required. Top that off with the probability that your fee didn’t include such mouse-nut engineering.




T. William (Bill) Allen, S.E.


Consulting Structural Engineers
V (949) 248-8588 F(949) 209-2509

-----Original Message-----
From: Daryl Richardson [mailto:h.d.richardson(--nospam--at)]
Sent: Thursday, June 14, 2007 10:28 AM
To: seaint(--nospam--at)
Subject: Re: Sole plate nailing




        I don't know your codes well enough to make an intelligent comment here; but if you're transferring shear from the sole plate to the floor plywood isn't the floor plywood nailing enough to transfer shear to all of the floor joists?


        Just a question out of curiosity and misunderstanding.




H. Daryl Richardson

----- Original Message -----

From: Bill Allen

Sent: Thursday, June 14, 2007 10:36 AM

Subject: RE: Sole plate nailing


The required penetration must be in the rim joist or blocking (joists perpendicular to the wall) or joist (joists parallel to the wall). After all, that’s what you are transferring the load into, right?


You can use a reduced capacity based on a linear interpolation between full capacity at 12D and half capacity at 6D. For a 16d Common that is 3-1/2” long and is nailed through 19/32” WSP, the penetration is 3.5-1.5-19/32=1.41”. Linearly interpolating between 0.5 at 6D and 1.0 at 12D, I get 79% of full capacity at 1.41/0.148=9.5D.


Note that the 2001 NDS reduces the required nail penetration to 10D for full capacity (see Table 11P, footnote 2) which means a 10d Common nail finally has full capacity when nailing two 2Xs together. Hallelujah! Using the same example as above, the 16d Common would have 94% of full capacity.


Of course, the whole model gets real messy when you consider the diaphragm nailing into the same rim joist.




T. William (Bill) Allen, S.E.


Consulting Structural Engineers
V (949) 248-8588 F(949) 209-2509

-----Original Message-----
From: ECVAl3(--nospam--at) [mailto:ECVAl3(--nospam--at)]
Sent: Thursday, June 14, 2007 8:14 AM
To: seaint(--nospam--at)
Subject: Sole plate nailing


When a sole plate for a wall is nailed to a wood floor, is the plywood on the joist or rim joist considered a part of the nail penetration or does the required penetration have to be into the joist or rim joist? UBC requires 16d's but with a 15/32" or 19/32" plywood floor diaphragm and a 1.1/2" sole plate, the 1.94" (12*D, NDS) required penetration into the joist is not met. NDS 12.3.4 specifies the penetrations is "..into the main member.."

S.Macie, P.E.



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